Number, NAPX-E4-NC27 SA, NAPX-E3-NC28 SA

Question

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Worked Solution

{{{workedSolution}}}

Variant 0

DifficultyLevel

706

Question

Xavier bought 2 identical tubs of liquid chlorine for his swimming pool.

After he used 34\dfrac{3}{4} of one tub in the pool, he had a total of 30 litres of chlorine left.

How many litres of chlorine were in one full tub?

Worked Solution

Let  V\ V = volume of 1 tub
14V+V\dfrac{1}{4} V + V = 30
54V\dfrac{5}{4} V = 30
∴V\therefore V = 30×45\dfrac{30 \times 4}{5}
= 24 litres

Question Type

Answer Box

Variables

Variable nameVariable value
question
Xavier bought 2 identical tubs of liquid chlorine for his swimming pool. After he used $\dfrac{3}{4}$ of one tub in the pool, he had a total of 30 litres of chlorine left. How many litres of chlorine were in one full tub?
workedSolution
sm_nogap Let $\ V$ = volume of 1 tub
| | | | --------------------: | -------------- | | $\dfrac{1}{4} V + V$ | \= 30| | $\dfrac{5}{4} V$ | \= 30 | | $\therefore V$| \= $\dfrac{30 \times 4}{5}$| || \= {{{correctAnswer0}}} {{{suffix0}}}|
correctAnswer0
24
prefix0
suffix0
litres

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer024

litres

Variant 1

DifficultyLevel

701

Question

Simpson bought 2 identical cans of paint for his mural.

After he used 14\dfrac{1}{4} of one can, he had a total of 14 litres of paint left.

How many litres of paint were in one full can?

Worked Solution

Let  V\ V = volume of 1 can
34V+V\dfrac{3}{4} V + V = 14
74V\dfrac{7}{4} V = 14
∴V\therefore V = 14×47\dfrac{14 \times 4}{7}
= 8 litres

Question Type

Answer Box

Variables

Variable nameVariable value
question
Simpson bought 2 identical cans of paint for his mural. After he used $\dfrac{1}{4}$ of one can, he had a total of 14 litres of paint left. How many litres of paint were in one full can?
workedSolution
sm_nogap Let $\ V$ = volume of 1 can
| | | | --------------------: | -------------- | | $\dfrac{3}{4} V + V$ | \= 14| | $\dfrac{7}{4} V$ | \= 14 | | $\therefore V$| \= $\dfrac{14 \times 4}{7}$| || \= {{{correctAnswer0}}} {{{suffix0}}}|
correctAnswer0
8
prefix0
suffix0
litres

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer08

litres

Variant 2

DifficultyLevel

710

Question

Roger bought 2 identical tubs of acid for his plastics factory.

After he used 13\dfrac{1}{3} of one tub, he had a total of 35 litres of acid left.

How many litres of acid were in one full tub?

Worked Solution

Let  V\ V = volume of 1 tub
23V+V\dfrac{2}{3} V + V = 35
53V\dfrac{5}{3} V = 35
∴V\therefore V = 35×35\dfrac{35 \times 3}{5}
= 21 litres

Question Type

Answer Box

Variables

Variable nameVariable value
question
Roger bought 2 identical tubs of acid for his plastics factory. After he used $\dfrac{1}{3}$ of one tub, he had a total of 35 litres of acid left. How many litres of acid were in one full tub?
workedSolution
sm_nogap Let $\ V$ = volume of 1 tub
| | | | --------------------: | -------------- | | $\dfrac{2}{3} V + V$ | \= 35| | $\dfrac{5}{3} V$ | \= 35 | | $\therefore V$| \= $\dfrac{35 \times 3}{5}$| || \= {{{correctAnswer0}}} {{{suffix0}}}|
correctAnswer0
21
prefix0
suffix0
litres

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer021

litres

Variant 3

DifficultyLevel

693

Question

Susan bought 2 identical cylinders of liquid hydrogen for her energy plant.

After she used 23\dfrac{2}{3} of one cylinder, she had a total of 8 litres of liquid hydrogen left.

How many litres of liquid hydrogen were in one full cylinder?

Worked Solution

Let  V\ V = volume of 1 cylinder
13V+V\dfrac{1}{3} V + V = 8
43V\dfrac{4}{3} V = 8
∴V\therefore V = 8×34\dfrac{8 \times 3}{4}
= 6 litres

Question Type

Answer Box

Variables

Variable nameVariable value
question
Susan bought 2 identical cylinders of liquid hydrogen for her energy plant. After she used $\dfrac{2}{3}$ of one cylinder, she had a total of 8 litres of liquid hydrogen left. How many litres of liquid hydrogen were in one full cylinder?
workedSolution
sm_nogap Let $\ V$ = volume of 1 cylinder
| | | | --------------------: | -------------- | | $\dfrac{1}{3} V + V$ | \= 8| | $\dfrac{4}{3} V$ | \= 8 | | $\therefore V$| \= $\dfrac{8 \times 3}{4}$| || \= {{{correctAnswer0}}} {{{suffix0}}}|
correctAnswer0
6
prefix0
suffix0
litres

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer06

litres

Variant 4

DifficultyLevel

689

Question

Brett bought 3 identical cans of paint for his mural.

After he used 12\dfrac{1}{2} of one can of paint, he had a total of 20 litres of paint left.

How many litres of paint are in one full can?

Worked Solution

Let  V\ V = volume of 1 can
12V+2V\dfrac{1}{2} V + 2V = 20
52V\dfrac{5}{2} V = 20
∴V\therefore V = 20×25\dfrac{20 \times 2}{5}
= 8 litres

Question Type

Answer Box

Variables

Variable nameVariable value
question
Brett bought 3 identical cans of paint for his mural. After he used $\dfrac{1}{2}$ of one can of paint, he had a total of 20 litres of paint left. How many litres of paint are in one full can?
workedSolution
sm_nogap Let $\ V$ = volume of 1 can
| | | | --------------------: | -------------- | | $\dfrac{1}{2} V + 2V$ | \= 20| | $\dfrac{5}{2} V$ | \= 20 | | $\therefore V$| \= $\dfrac{20 \times 2}{5}$| || \= {{{correctAnswer0}}} {{{suffix0}}}|
correctAnswer0
8
prefix0
suffix0
litres

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer08

litres

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