Measurement, NAPX9-TLF-CA32 v3

Question

{{{question}}}

Worked Solution

{{{workedSolution}}}

Variant 0

DifficultyLevel

685

Question

A logo is shaped like a hexagon.

The dimensions are given from the top view of the logo.



What is the total area of the logo?

Worked Solution
Area = Area of rectangle + 2 × Area of triangle
= (13 × 22) + 2 × (12×22×3)\bigg( \dfrac{1}{2} × 22 × 3 \bigg)
= 286 + 66
= 352 cm2^2

Question Type

Answer Box

Variables

Variable nameVariable value
question
A logo is shaped like a hexagon. The dimensions are given from the top view of the logo.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2021/09/NAPX9-TLF-32.svg 320 indent3 vpad
What is the total area of the logo?
workedSolution
||| |-|-| |Area|= Area of rectangle + 2 × Area of triangle| ||= (13 × 22) + 2 × $\bigg( \dfrac{1}{2} × 22 × 3 \bigg)$| ||= 286 + 66| ||= {{{correctAnswer0}}} {{{suffix0}}}|
correctAnswer0
352
prefix0
suffix0
cm$^2$

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer0352

cm2^2

Variant 1

DifficultyLevel

684

Question

A logo is shaped like a hexagon.

The dimensions are given from the top view of the logo.



What is the total area of the logo?

Worked Solution
Area = Area of rectangle + 2 × Area of triangle
= (40 × 19) + 2 × (12×40×7)\bigg( \dfrac{1}{2} × 40 × 7 \bigg)
= 760 + 280
= 1040 cm2^2

Question Type

Answer Box

Variables

Variable nameVariable value
question
A logo is shaped like a hexagon. The dimensions are given from the top view of the logo.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2022/08/Measurement_NAPX9-TLF-CA32-v3_v1.svg 350 indent3 vpad
What is the total area of the logo?
workedSolution
||| |-|-| |Area|= Area of rectangle + 2 × Area of triangle| ||= (40 × 19) + 2 × $\bigg( \dfrac{1}{2} × 40 × 7 \bigg)$| ||= 760 + 280| ||= {{{correctAnswer0}}} {{{suffix0}}}|
correctAnswer0
1040
prefix0
suffix0
cm$^2$

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer01040

cm2^2

Variant 2

DifficultyLevel

679

Question

A resort's swimming pool is shaped like a hexagon.

The dimensions are given from the top view of the swimming pool.



What is the total area of the swimming pool?

Worked Solution
Area = Area of rectangle + 2 × Area of triangle
= (3 × 4) + 2 × (12×3×5)\bigg( \dfrac{1}{2} × 3 × 5 \bigg)
= 12 + 15
= 27 m2^2

Question Type

Answer Box

Variables

Variable nameVariable value
question
A resort's swimming pool is shaped like a hexagon. The dimensions are given from the top view of the swimming pool.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2022/08/Measurement_NAPX9-TLF-CA32-v3_v2.svg 420 indent vpad
What is the total area of the swimming pool?
workedSolution
||| |-|-| |Area|= Area of rectangle + 2 × Area of triangle| ||= (3 × 4) + 2 × $\bigg( \dfrac{1}{2} × 3 × 5 \bigg)$| ||= 12 + 15| ||= {{{correctAnswer0}}} {{{suffix0}}}|
correctAnswer0
27
prefix0
suffix0
m$^2$

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer027

m2^2

Variant 3

DifficultyLevel

679

Question

An earring is shaped like a hexagon.

The dimensions are given from the top view of the earring.



What is the total area of the earring?

Worked Solution
Area = Area of rectangle + 2 × Area of triangle
= (6 × 2) + 2 × (12×6×1)\bigg( \dfrac{1}{2} × 6 × 1 \bigg)
= 12 + 6
= 18 cm2^2

Question Type

Answer Box

Variables

Variable nameVariable value
question
An earring is shaped like a hexagon. The dimensions are given from the top view of the earring.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2022/08/Measurement_NAPX9-TLF-CA32-v3_v3.svg 270 indent3 vpad
What is the total area of the earring?
workedSolution
||| |-|-| |Area|= Area of rectangle + 2 × Area of triangle| ||= (6 × 2) + 2 × $\bigg( \dfrac{1}{2} × 6 × 1 \bigg)$| ||= 12 + 6| ||= {{{correctAnswer0}}} {{{suffix0}}}|
correctAnswer0
18
prefix0
suffix0
cm$^2$

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer018

cm2^2

Variant 4

DifficultyLevel

681

Question

A holiday unit is shaped like a hexagon.

The dimensions of its floor plan are shown below.



What is the total area of the holiday unit?

Worked Solution
Area = Area of rectangle + 2 × Area of triangle
= (14 × 9) + 2 × (12×9×3)\bigg( \dfrac{1}{2} × 9 × 3 \bigg)
= 126 + 27
= 153 m2^2

Question Type

Answer Box

Variables

Variable nameVariable value
question
A holiday unit is shaped like a hexagon. The dimensions of its floor plan are shown below.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2022/08/Measurement_NAPX9-TLF-CA32-v3_v4.svg 480 indent vpad
What is the total area of the holiday unit?
workedSolution
||| |-|-| |Area|= Area of rectangle + 2 × Area of triangle| ||= (14 × 9) + 2 × $\bigg( \dfrac{1}{2} × 9 × 3 \bigg)$| ||= 126 + 27| ||= {{{correctAnswer0}}} {{{suffix0}}}|
correctAnswer0
153
prefix0
suffix0
m$^2$

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer0153

m2^2

Variant 5

DifficultyLevel

687

Question

A place mat is shaped like a hexagon.

The dimensions are given from the top view of the place mat.



What is the total area of the place mat?

Worked Solution
Area = Area of rectangle + Area of triangle 1 + Area of triangle 2
= (24 × 27) + (12×27×6)\bigg( \dfrac{1}{2} × 27 × 6 \bigg) + (12×27×5)\bigg( \dfrac{1}{2} × 27 × 5 \bigg)
= 648 + 81 + 67.5
= 796.5 cm2^2

Question Type

Answer Box

Variables

Variable nameVariable value
question
A place mat is shaped like a hexagon. The dimensions are given from the top view of the place mat.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2022/08/Measurement_NAPX9-TLF-CA32-v3_v5.svg 380 indent vpad
What is the total area of the place mat?
workedSolution
||| |-|-| |Area|= Area of rectangle + Area of triangle 1 + Area of triangle 2| ||= (24 × 27) + $\bigg( \dfrac{1}{2} × 27 × 6 \bigg)$ + $\bigg( \dfrac{1}{2} × 27 × 5 \bigg)$|| ||= 648 + 81 + 67.5| ||= {{{correctAnswer0}}} {{{suffix0}}}|
correctAnswer0
796.5
prefix0
suffix0
cm$^2$

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer0796.5

cm2^2

Tags

  • ms_ca