Algebra, NAPX-E4-CA19, NAPX-E3-CA23

Question

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Worked Solution

{{{workedSolution}}}

Variant 0

DifficultyLevel

624

Question

Clinton designs a line of tiles that repeats 6 different tiles in the same order, as shown below.



Each tile costs $7.50 and Clinton uses $240 worth of tiles.

Which of these is the last tile in his line of tiles?

Worked Solution
Total number of tiles used = 2407.50\dfrac{240}{7.50}
= 32

∴ Five full patterns of 6 tiles + 2 (i.e. the last tile is the second in the pattern)

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
Clinton designs a line of tiles that repeats 6 different tiles in the same order, as shown below.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2018/05/NAPX-E4-CA19.svg 650 indent vpad
Each tile costs $7.50 and Clinton uses $240 worth of tiles. Which of these is the last tile in his line of tiles?
workedSolution
| | | | ------------: | ---------- | | Total number of tiles used | = $\dfrac{240}{7.50}$ | | |= 32 |

∴ Five full patterns of 6 tiles + 2 (i.e. the last tile is the second in the pattern) {{{correctAnswer}}}
correctAnswer
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2018/05/NAPX-E4-CA19b.svg 65 indent vpad

Answers

Is Correct?Answer
x
✓
x
x
x

Variant 1

DifficultyLevel

629

Question

Mr Earp designs a line of tiles that repeats 6 different tiles in the same order, as shown below.



Each tile costs $13.70 and Mr Earp uses $548 worth of tiles.

Which of these is the last tile in his line of tiles?

Worked Solution
Total number of tiles used = 54813.70\dfrac{548}{13.70}
= 40

∴ Six full patterns of 6 tiles + 4 (i.e. the last tile is the 4th in the pattern)

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
Mr Earp designs a line of tiles that repeats 6 different tiles in the same order, as shown below.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2018/05/NAPX-E4-CA19.svg 650 indent vpad
Each tile costs $13.70 and Mr Earp uses $548 worth of tiles. Which of these is the last tile in his line of tiles?
workedSolution
| | | | ------------: | ---------- | | Total number of tiles used | = $\dfrac{548}{13.70}$ | | |= 40 |

∴ Six full patterns of 6 tiles + 4 (i.e. the last tile is the 4th in the pattern) {{{correctAnswer}}}
correctAnswer
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2018/05/NAPX-E4-CA19d.svg 65 indent vpad

Answers

Is Correct?Answer
x
x
x
✓
x

Variant 2

DifficultyLevel

631

Question

Klim decorated his fence with a line of tiles that repeats 6 different tiles in the same order, as shown below.



Each tile costs $9.50 and Klim uses $256.50 worth of tiles.

Which of these is the last tile in his line of tiles?

Worked Solution
Total number of tiles used = 256.509.50\dfrac{256.50}{9.50}
= 27

∴ Four full patterns of 6 tiles + 3 (i.e. the last tile is the 3rd in the pattern)

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
Klim decorated his fence with a line of tiles that repeats 6 different tiles in the same order, as shown below.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2018/05/NAPX-E4-CA19.svg 650 indent vpad
Each tile costs $9.50 and Klim uses $256.50 worth of tiles. Which of these is the last tile in his line of tiles?
workedSolution
| | | | ------------: | ---------- | | Total number of tiles used | = $\dfrac{256.50}{9.50}$ | | |= 27 |

∴ Four full patterns of 6 tiles + 3 (i.e. the last tile is the 3rd in the pattern) {{{correctAnswer}}}
correctAnswer
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2018/05/NAPX-E4-CA19c.svg 65 indent vpad

Answers

Is Correct?Answer
x
x
✓
x
x

Variant 3

DifficultyLevel

633

Question

Danny decorated his patio with a line of tiles that repeats 6 different tiles in the same order, as shown below.



Each tile costs $11.50 and Danny uses $448.50 worth of tiles.

Which of these is the last tile in his line of tiles?

Worked Solution
Total number of tiles used = 448.5011.50\dfrac{448.50}{11.50}
= 39
Total number of repititions = 396\dfrac{39}{6}
= 6 remainder 3

∴ Six full patterns of 6 tiles + 3

∴ The last tile is the 3rd tile in the pattern

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
Danny decorated his patio with a line of tiles that repeats 6 different tiles in the same order, as shown below.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2023/08/Algebra-NAPX-E4-CA19-v3-min.svg 650 indent vpad
Each tile costs $11.50 and Danny uses $448.50 worth of tiles. Which of these is the last tile in his line of tiles?
workedSolution
| | | | ------------: | ---------- | | Total number of tiles used | = $\dfrac{448.50}{11.50}$ | | |= 39 | | Total number of repititions | = $\dfrac{39}{6}$ | | |= 6 remainder 3 |

∴ Six full patterns of 6 tiles + 3 ∴ The last tile is the 3rd tile in the pattern {{{correctAnswer}}}
correctAnswer
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2018/05/NAPX-E4-CA19b.svg 65 indent vpad

Answers

Is Correct?Answer
x
x
x
✓
x

Variant 4

DifficultyLevel

637

Question

Shayna decorated her ensuite with a line of tiles that repeats 6 different tiles in the same order, as shown below.



Each tile costs $14.20 and Shayna uses $1263.80 worth of tiles.

Which of these is the last tile in her line of tiles?

Worked Solution
Total number of tiles used = 1263.8014.20\dfrac{1263.80}{14.20}
= 89
Total number of repititions = 896\dfrac{89}{6}
= 14 remainder 5

∴ 14 full patterns of 6 tiles + 5

∴ The last tile is the 5th tile in the pattern

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
Shayna decorated her ensuite with a line of tiles that repeats 6 different tiles in the same order, as shown below.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2023/08/Algebra-NAPX-E4-CA19-v3-min.svg 650 indent vpad
Each tile costs $14.20 and Shayna uses $1263.80 worth of tiles. Which of these is the last tile in her line of tiles?
workedSolution
| | | | ------------: | ---------- | | Total number of tiles used | = $\dfrac{1263.80}{14.20}$ | | |= 89 | | Total number of repititions | = $\dfrac{89}{6}$ | | |= 14 remainder 5 |

∴ 14 full patterns of 6 tiles + 5 ∴ The last tile is the 5th tile in the pattern {{{correctAnswer}}}
correctAnswer
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2018/05/NAPX-E4-CA19f.svg 65 indent vpad

Answers

Is Correct?Answer
x
x
x
x
✓

Variant 5

DifficultyLevel

639

Question

Lincoln decorated his outdoor barbecue area with a line of tiles that repeats 6 different tiles in the same order, as shown below.



Each tile costs $18.35 and Lincoln uses $1137.70 worth of tiles.

Which of these is the last tile in his line of tiles?

Worked Solution
Total number of tiles used = 1137.7018.35\dfrac{1137.70}{18.35}
= 62
Total number of repititions = 626\dfrac{62}{6}
= 10 remainder 2

∴ 10 full patterns of 6 tiles + 2 ∴ The last tile is the 2nd tile in the pattern

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
Lincoln decorated his outdoor barbecue area with a line of tiles that repeats 6 different tiles in the same order, as shown below.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2023/08/Algebra-NAPX-E4-CA19-v3-min.svg 650 indent vpad
Each tile costs $18.35 and Lincoln uses $1137.70 worth of tiles. Which of these is the last tile in his line of tiles?
workedSolution
| | | | ------------: | ---------- | | Total number of tiles used | = $\dfrac{1137.70}{18.35}$ | | |= 62 | | Total number of repititions | = $\dfrac{62}{6}$ | | |= 10 remainder 2 |

∴ 10 full patterns of 6 tiles + 2 ∴ The last tile is the 2nd tile in the pattern {{{correctAnswer}}}
correctAnswer
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2018/05/NAPX-E4-CA19c.svg 65 indent vpad

Answers

Is Correct?Answer
x
✓
x
x
x

Tags

  • staging_suejones