30255

Question

{{question}}

Worked Solution

{{{solution}}}

Variant 0

DifficultyLevel

543

Question

Joseph had a weekly allowance of $100. In one week, he spent $40 on food, $20 on transportation and another $20 on clothes.

What percentage of his allowance did he spend?

Worked Solution

Total spending
= 40 + 20 + 20
= $80

∴\therefore Percentage of allowance spent
= 80100×100\dfrac{80}{100} \times 100%
= 80%

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
Joseph had a weekly allowance of $100. In one week, he spent $40 on food, $20 on transportation and another $20 on clothes. What percentage of his allowance did he spend?
solution
sm_nogap Total spending
> > | | > > | ------- | > > | = 40 + 20 + 20 | > > | = $80 |

sm_nogap $\therefore$ Percentage of allowance spent
> > | | > > | ------- | > > | = $\dfrac{80}{100} \times 100%$ | > > | = 80% |
correctAnswer
80%

Answers

Is Correct?Answer
x

50%

x

60%

x

70%

✓

80%

Variant 1

DifficultyLevel

543

Question

Lyn had 8 kg of sugar. She used 3 kg to bake cupcakes, 1 kg to make lemonade and 2 kg to make jam.

What percentage of her total sugar did Lyn use?

Worked Solution

Total sugar used
= 3 + 1 + 2
= 6 kg

Percentage of sugar used
= 68×100\dfrac{6}{8} \times 100
= 34×\dfrac{3}{4} \times 100
= 75%

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
Lyn had 8 kg of sugar. She used 3 kg to bake cupcakes, 1 kg to make lemonade and 2 kg to make jam. What percentage of her total sugar did Lyn use?
solution
sm_nogap Total sugar used
> > | | > > | ------- | > > | = 3 + 1 + 2 | > > | = 6 kg|

sm_nogap Percentage of sugar used
> > | | > > | ------- | > > | = $\dfrac{6}{8} \times 100$ | > > | = $\dfrac{3}{4} \times$ 100 | > > | = 75% |
correctAnswer
75%

Answers

Is Correct?Answer
x

65%

x

70%

✓

75%

x

80%

Variant 2

DifficultyLevel

543

Question

A builder purchased 50 bags of cement to build an outdoor shed.

He used 10 bags for the footings, 15 bags for the slab and 5 bags for the path.

What percentage of the cement bags purchased did the builder use?

Worked Solution

Total bags of cement used
= 10 + 15 + 5
= 30

Percentage of cement bags used
= 3050×100\dfrac{30}{50} \times 100
= 0.6 ×\times 100
= 60%

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
A builder purchased 50 bags of cement to build an outdoor shed. He used 10 bags for the footings, 15 bags for the slab and 5 bags for the path. What percentage of the cement bags purchased did the builder use?
solution
sm_nogap Total bags of cement used
> > | | > > | ------- | > > | = 10 + 15 + 5 | > > | = 30 |

sm_nogap Percentage of cement bags used
> > | | > > | ------- | > > | = $\dfrac{30}{50} \times 100$ | > > | = 0.6 $\times$ 100 | > > | = 60% |
correctAnswer
60%

Answers

Is Correct?Answer
x

25%

x

30%

✓

60%

x

70%

Variant 3

DifficultyLevel

543

Question

Barry weighed 80 kg and started doing triathlons.

He lost 2.8 kg in the 1st month, 3 kg in the 2nd month and 2.2 kg in the 3rd month.

What percentage of his original weight did Barry lose?

Worked Solution

Total kilograms lost
= 2.8 + 3 + 2.2
= 8.0

Percentage of original weight lost
= 880×100\dfrac{8}{80} \times 100
= 0.1 ×\times 100
= 10%

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
Barry weighed 80 kg and started doing triathlons. He lost 2.8 kg in the 1st month, 3 kg in the 2nd month and 2.2 kg in the 3rd month. What percentage of his original weight did Barry lose?
solution
sm_nogap Total kilograms lost
> > | | > > | ------- | > > | = 2.8 + 3 + 2.2 | > > | = 8.0 |

sm_nogap Percentage of original weight lost
> > | | > > | ------- | > > | = $\dfrac{8}{80} \times 100$ | > > | = 0.1 $\times$ 100 | > > | = 10% |
correctAnswer
10%

Answers

Is Correct?Answer
x

8%

✓

10%

x

15%

x

20%

Variant 4

DifficultyLevel

543

Question

Maurice bought a family size pizza cut into 12 equal slices.

He ate 4 slices, his brother Barry ate 2 slices and his other brother Robin ate 3 slices.

What percentage of Maurice’s pizza was eaten?

Worked Solution

Total pizza slices eaten
= 4 + 2 + 3
= 9

Percentage of pizza eaten
= 912×100\dfrac{9}{12} \times 100
= 34×100\dfrac{3}{4} \times 100
= 75%

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
Maurice bought a family size pizza cut into 12 equal slices. He ate 4 slices, his brother Barry ate 2 slices and his other brother Robin ate 3 slices. What percentage of Maurice’s pizza was eaten?
solution
sm_nogap Total pizza slices eaten
> > | | > > | ------- | > > | = 4 + 2 + 3 | > > | = 9 |

sm_nogap Percentage of pizza eaten
> > | | > > | ------- | > > | = $\dfrac{9}{12} \times 100$ | > > | = $\dfrac{3}{4} \times 100$ | > > | = 75% |
correctAnswer
75%

Answers

Is Correct?Answer
x

80%

✓

75%

x

70%

x

65%