Algebra, NAP_70042

Question

Maurice finds that by wearing different combinations of the jackets, shirts and pairs of trousers that he owns, he can make up 180 different outfits. If Maurice owns 9 jackets and 2 shirts, how many pairs of trousers does he own?

Worked Solution

Let x\large x be the number of pairs of trousers Maurice owns, then
9 ×\times 2 × x\times\ \large x = 180
x\large x = 18018\dfrac{180}{18}
= {{{correctAnswer}}}

∴\therefore Maurice owns {{{correctAnswer}}} pairs of trousers.

Variant 0

DifficultyLevel

662

Question

Maurice finds that by wearing different combinations of the jackets, shirts and pairs of trousers that he owns, he can make up 180 different outfits. If Maurice owns 9 jackets and 2 shirts, how many pairs of trousers does he own?

Worked Solution

Let x\large x be the number of pairs of trousers Maurice owns, then
9 ×\times 2 × x\times\ \large x = 180
x\large x = 18018\dfrac{180}{18}
= 10

∴\therefore Maurice owns 10 pairs of trousers.

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
correctAnswer
10

Answers

Is Correct?Answer
x

2

x

5

✓

10

x

15

Tags

  • staging_suejones