20354

Question

A {{type}} has a hub with {{measure1}} of {{length1}} millimetres and an outer rubber layer with a width of {{length2}} millimetres.

{{image}}

What distance, in millimetres, would the truck cover in one full rotation of the wheel?

Worked Solution

Radius of wheel = {{length1}} + {{length2}}
= {{length3}} mm
\therefore Distance = 2 × π × r\times\ \large \pi\ \times\ \large r
= {{{correctAnswer}}}

Variant 0

DifficultyLevel

577

Question

A truck wheel has a hub with radius of 250 millimetres and an outer rubber layer with a width of 150 millimetres.

What distance, in millimetres, would the truck cover in one full rotation of the wheel?

Worked Solution

Radius of wheel = 250 + 150
= 400 mm
\therefore Distance = 2 × π × r\times\ \large \pi\ \times\ \large r
= 2×π×4002 \times\large \pi\normalsize\times 400

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
type
truck wheel
measure1
radius
length1
250
length2
150
image
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2021/01/5var_320_150mm.svg 350 indent vpad
length3
400
correctAnswer
$2 \times\large \pi\normalsize\times 400$

Answers

Is Correct?Answer
x

π×1502\large \pi \normalsize \times 150^2

x

π×4002\large \pi \normalsize \times 400^2

x

2×π×1502 \times \large \pi\normalsize \times 150

2×π×4002 \times\large \pi\normalsize\times 400


Variant 1

DifficultyLevel

579

Question

A coal truck wheel has a hub with radius of 2400 millimetres and an outer rubber layer with a width of 600 millimetres.

What distance, in millimetres, would the truck cover in one full rotation of the wheel?

Worked Solution

Radius of wheel = 2400 + 600
= 3000 mm
\therefore Distance = 2 × π × r\times\ \large \pi\ \times\ \large r
= π×6000\large \pi \normalsize \times 6000

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
type
coal truck wheel
measure1
radius
length1
2400
length2
600
image
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2021/01/5var_320_600mm.svg 350 indent vpad
length3
3000
correctAnswer
$\large \pi \normalsize \times 6000$

Answers

Is Correct?Answer
x

π×12000\large \pi \normalsize \times 12000

x

π×60002\large \pi\normalsize\times 6000^2

π×6000\large \pi \normalsize \times 6000

x

π×30002\large \pi \normalsize \times 3000^2


Variant 2

DifficultyLevel

577

Question

A monster truck wheel has a hub with radius of 3200 millimetres and an outer rubber layer with a width of 500 millimetres.

What distance, in millimetres, would the truck cover in one full rotation of the wheel?

Worked Solution

Radius of wheel = 3200 + 500
= 3700 mm
\therefore Distance = 2 × π × r\times\ \large \pi\ \times\ \large r
= 2×π×37002 \times \large \pi \normalsize\times 3700

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
type
monster truck wheel
measure1
radius
length1
3200
length2
500
image
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2021/01/5var_320_500mm.svg 350 indent vpad
length3
3700
correctAnswer
$2 \times \large \pi \normalsize\times 3700$

Answers

Is Correct?Answer
x

π×37002\large \pi \normalsize \times 3700^2

2×π×37002 \times \large \pi \normalsize\times 3700

x

π×74002\large \pi \normalsize\times 7400^2

x

2×π×74002 \times \large \pi \normalsize \times 7400


Variant 3

DifficultyLevel

577

Question

A truck tyre has a hub with radius of 380 millimetres and an outer rubber layer with a width of 140 millimetres.

What distance, in millimetres, would the truck cover in one full rotation of the wheel?

Worked Solution

Radius of wheel = 380 + 140
= 520 mm
\therefore Distance = 2 × π × r\times\ \large \pi\ \times\ \large r
= 2×π×5202 \times \large \pi \normalsize\times 520

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
type
truck tyre
measure1
radius
length1
380
length2
140
image
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2021/01/5var_320_140mm.svg 350 indent vpad
length3
520
correctAnswer
$2 \times \large \pi \normalsize\times 520$

Answers

Is Correct?Answer
x

π×1402\large \pi \normalsize \times 140^2

x

π×5202\large \pi \normalsize \times 520^2

x

2×π×1402 \times \large \pi \normalsize \times 140

2×π×5202 \times \large \pi \normalsize\times 520


Variant 4

DifficultyLevel

580

Question

A mining truck tyre has a hub with radius of 1900 millimetres and an outer rubber layer with a width of 600 millimetres.

What distance, in millimetres, would the truck cover in one full rotation of the wheel?

Worked Solution

Radius of wheel = 1900 + 600
= 2500 mm
\therefore Distance = 2 × π × r\times\ \large \pi\ \times\ \large r
= π×5000\large \pi \normalsize \times 5000

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
type
mining truck tyre
measure1
radius
length1
1900
length2
600
image
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2021/01/5var_320_600mm.svg 350 indent vpad
length3
2500
correctAnswer
$\large \pi \normalsize \times 5000$

Answers

Is Correct?Answer
x

π×1200\large \pi \normalsize \times 1200

x

π×6002\large \pi \normalsize \times 600^2

π×5000\large \pi \normalsize \times 5000

x

π×25002\large \pi \normalsize\times 2500^2