Measurement, NAPX-I4-CA29 SA

Question

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Worked Solution

{{{workedSolution}}}

Variant 0

DifficultyLevel

731

Question

An archery target has the following dimensions.



What is the area of the entire target?

Use  π\large \pi = 3.14  and round your answer to the nearest square centimetre.

Worked Solution
Area = πr\large \pi r2^2
= π\large \pi × (4+3.5×4)2\times\ (4 + 3.5 \times 4)^2
= 3.14 × 182\times\ 18^2
= 1017.36...
= 1017 cm2^2

Question Type

Answer Box

Variables

Variable nameVariable value
question
An archery target has the following dimensions.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2018/04/NAPX-I4-CA29.svg 420 indent3 vpad
What is the area of the entire target? Use  $\large \pi$ = 3.14  and round your answer to the nearest square centimetre.
workedSolution
||| |-|-| |Area|= $\large \pi r$$^2$| ||= $\large \pi$ $\times\ (4 + 3.5 \times 4)^2$| ||= 3.14 $\times\ 18^2$| ||= 1017.36...| ||= {{{correctAnswer0}}} {{{suffix0}}}|
correctAnswer0
1017
prefix0
suffix0
cm$^2$

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer01017

cm2^2

Variant 1

DifficultyLevel

730

Question

A small plate has the following dimensions.



What is the area of the entire plate?

Use  π\large \pi = 3.14  and round your answer to the nearest square centimetre.

Worked Solution
Area = πr\large \pi r2^2
= π\large \pi × (3.5+3+4+5)2\times\ (3.5 + 3 + 4 + 5)^2
= 3.14 × 15.52\times\ 15.5^2
= 754.385
= 754 cm2^2

Question Type

Answer Box

Variables

Variable nameVariable value
question
A small plate has the following dimensions.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2022/08/Measurement-NAPX-I4-CA29-SA_1nts.svg 500 indent1 vpad
What is the area of the entire plate? Use  $\large \pi$ = 3.14  and round your answer to the nearest square centimetre.
workedSolution
||| |-|-| |Area|= $\large \pi r$$^2$| ||= $\large \pi$ $\times\ (3.5 + 3 + 4 + 5)^2$| ||= 3.14 $\times\ 15.5^2$| ||= 754.385| ||= {{{correctAnswer0}}} {{{suffix0}}}|
correctAnswer0
754
prefix0
suffix0
cm$^2$

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer0754

cm2^2

Variant 2

DifficultyLevel

729

Question

The base of a cat basket has the following dimensions.



What is the area of the entire base?

Use  π\large \pi = 3.14  and round your answer to the nearest square centimetre.

Worked Solution
Area = πr\large \pi r2^2
= π\large \pi × (10+8×4)2\times\ (10 + 8 \times 4)^2
= 3.14 × 422\times\ 42^2
= 5538.96
= 5539 cm2^2

Question Type

Answer Box

Variables

Variable nameVariable value
question
The base of a cat basket has the following dimensions.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2022/08/Measurement-NAPX-I4-CA29-SA_2nts.svg 500 indent1 vpad
What is the area of the entire base? Use  $\large \pi$ = 3.14  and round your answer to the nearest square centimetre.
workedSolution
||| |-|-| |Area|= $\large \pi r$$^2$| ||= $\large \pi$ $\times\ (10 + 8 \times 4)^2$| ||= 3.14 $\times\ 42^2$| ||= 5538.96| ||= {{{correctAnswer0}}} {{{suffix0}}}|
correctAnswer0
5539
prefix0
suffix0
cm$^2$

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer05539

cm2^2

Variant 3

DifficultyLevel

728

Question

A placemat has the following dimensions.



What is the area of the entire placemat?

Use  π\large \pi = 3.14  and round your answer to the nearest square centimetre.

Worked Solution
Area = πr\large \pi r2^2
= π\large \pi × (7.5+6.5×4)2\times\ (7.5 + 6.5 \times 4)^2
= 3.14 × 33.52\times\ 33.5^2
= 3523.865
= 3524 cm2^2

Question Type

Answer Box

Variables

Variable nameVariable value
question
A placemat has the following dimensions.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2022/08/Measurement-NAPX-I4-CA29-SA_3nts.svg 500 indent1 vpad
What is the area of the entire placemat? Use  $\large \pi$ = 3.14  and round your answer to the nearest square centimetre.
workedSolution
||| |-|-| |Area|= $\large \pi r$$^2$| ||= $\large \pi$ $\times\ (7.5 + 6.5 \times 4)^2$| ||= 3.14 $\times\ 33.5^2$| ||= 3523.865| ||= {{{correctAnswer0}}} {{{suffix0}}}|
correctAnswer0
3524
prefix0
suffix0
cm$^2$

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer03524

cm2^2

Variant 4

DifficultyLevel

733

Question

A large circular sheet has the following dimensions.



What is the area of the entire sheet?

Use  π\large \pi = 3.14  and round your answer to the nearest square metre.

Worked Solution
Area = πr\large \pi r2^2
= π\large \pi × (0.75+0.8×4)2\times\ (0.75 + 0.8 \times 4)^2
= 3.14 × 3.952\times\ 3.95^2
= 48.99185
= 49 m2^2

Question Type

Answer Box

Variables

Variable nameVariable value
question
A large circular sheet has the following dimensions.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2022/08/Measurement-NAPX-I4-CA29-SA_4nts.svg 500 indent1 vpad
What is the area of the entire sheet? Use  $\large \pi$ = 3.14  and round your answer to the nearest square metre.
workedSolution
||| |-|-| |Area|= $\large \pi r$$^2$| ||= $\large \pi$ $\times\ (0.75 + 0.8 \times 4)^2$| ||= 3.14 $\times\ 3.95^2$| ||= 48.99185| ||= {{{correctAnswer0}}} {{{suffix0}}}|
correctAnswer0
49
prefix0
suffix0
m$^2$

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer049

m2^2

Variant 5

DifficultyLevel

737

Question

A baby's play mat has the following dimensions.



What is the area of the entire play mat?

Use  π\large \pi = 3.14  and round your answer to the nearest tenth of a square metre.

Worked Solution

Radius of inner circle = 25 cm = 0.25 m
Area = πr\large \pi r2^2
= π\large \pi × (0.25+0.2×4)2\times\ (0.25 + 0.2 \times 4)^2
= 3.14 × 1.052\times\ 1.05^2
= 3.46185
= 3.5 m2^2

Question Type

Answer Box

Variables

Variable nameVariable value
question
A baby's play mat has the following dimensions.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2022/08/Measurement-NAPX-I4-CA29-SA_5nts.svg 500 indent1 vpad
What is the area of the entire play mat? Use  $\large \pi$ = 3.14  and round your answer to the nearest tenth of a square metre.
workedSolution
Radius of inner circle = 25 cm = 0.25 m
||| |-|-| |Area|= $\large \pi r$$^2$| ||= $\large \pi$ $\times\ (0.25 + 0.2 \times 4)^2$| ||= 3.14 $\times\ 1.05^2$| ||= 3.46185| ||= {{{correctAnswer0}}} {{{suffix0}}}|
correctAnswer0
3.5
prefix0
suffix0
m$^2$

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer03.5

m2^2

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