20133

Question

Polly, Roger and Milly are splitting up two identical chocolate bars.

Polly takes 14\dfrac{1}{4} of the first chocolate bar and 38\dfrac{3}{8} of the second bar.

Roger takes 12\dfrac{1}{2} of the first chocolate bar and 14\dfrac{1}{4} of the second bar.

What fraction of each bar did Milly get?

Worked Solution

1st bar: 1−(14+12)=141 - \bigg( \dfrac{1}{4} + \dfrac{1}{2} \bigg) = \dfrac{1}{4}

2nd bar: 1−(38+14)=381 - \bigg( \dfrac{3}{8} + \dfrac{1}{4} \bigg) = \dfrac{3}{8}

∴\therefore {{{correctAnswer}}}

Variant 0

DifficultyLevel

617

Question

Polly, Roger and Milly are splitting up two identical chocolate bars.

Polly takes 14\dfrac{1}{4} of the first chocolate bar and 38\dfrac{3}{8} of the second bar.

Roger takes 12\dfrac{1}{2} of the first chocolate bar and 14\dfrac{1}{4} of the second bar.

What fraction of each bar did Milly get?

Worked Solution

1st bar: 1−(14+12)=141 - \bigg( \dfrac{1}{4} + \dfrac{1}{2} \bigg) = \dfrac{1}{4}

2nd bar: 1−(38+14)=381 - \bigg( \dfrac{3}{8} + \dfrac{1}{4} \bigg) = \dfrac{3}{8}

∴\therefore Milly got 14\dfrac{1}{4} of the first bar and 38\dfrac{3}{8} of the second bar.

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
correctAnswer
Milly got $\dfrac{1}{4}$ of the first bar and $\dfrac{3}{8}$ of the second bar.

Answers

Is Correct?Answer
x

Milly got 14\dfrac{1}{4} of each chocolate bar.

x

Milly got 18\dfrac{1}{8} of the first bar and 14\dfrac{1}{4} of the second bar.

✓

Milly got 14\dfrac{1}{4} of the first bar and 38\dfrac{3}{8} of the second bar.

x

Milly got 18\dfrac{1}{8} of the first bar and 38\dfrac{3}{8} of the second bar.