Statistics and Probability, NAPX-L4-CA07 o2

Question

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Worked Solution

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Variant 0

DifficultyLevel

540

Question

Albert runs a pet store that sells pure breed dogs.

He has a total of 36 dogs in the shop from different breeds.


Breed Number of dogs
Pug 4
Labrador 16
Bulldog 6
Chihuahua 5
Husky 5


If one of Albert's dogs is chosen at random, what is the probability it will be either a labrador or a bulldog?

Worked Solution
PP(L or B) = Number of L and BTotal puppies\dfrac{\text{Number of L and B}}{\text{Total puppies}}
= 16+636\dfrac{16 + 6}{36}
= 1118\dfrac{11}{18}

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
Albert runs a pet store that sells pure breed dogs. He has a total of 36 dogs in the shop from different breeds.
>>| **Breed** | **Number of dogs** | |:-:|:-:| | Pug| 4| | Labrador| 16| | Bulldog| 6| | Chihuahua| 5| | Husky | 5|

If one of Albert's dogs is chosen at random, what is the probability it will be either a labrador or a bulldog?
workedSolution
| | | | ------------- | ---------- | | $P$(L or B) | \= $\dfrac{\text{Number of L and B}}{\text{Total puppies}}$ | | | \= $\dfrac{16 + 6}{36}$ | | | \= {{{correctAnswer}}} |
correctAnswer
$\dfrac{11}{18}$

Answers

Is Correct?Answer
x

49\dfrac{4}{9}

x

916\dfrac{9}{16}

✓

1118\dfrac{11}{18}

x

94\dfrac{9}{4}

Variant 1

DifficultyLevel

540

Question

Nerida breeds 4 different types of hounds.

Last year her hounds produced a total of 32 puppies.


Hound Type Number of puppies
Beagle 6
Ridgeback 8
Bloodhound 12
Dachshund 6


If one puppy is chosen at random, what is the probability it will be either a Ridgeback or a Dachshund?

Worked Solution
PP(R or D) = Number of R and DTotal puppies\dfrac{\text{Number of R and D}}{\text{Total puppies}}
= 8+632\dfrac{8 + 6}{32}
= 716\dfrac{7}{16}

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
Nerida breeds 4 different types of hounds. Last year her hounds produced a total of 32 puppies.
>>| **Hound Type**| **Number of puppies** | |:-:|:-:| | Beagle| 6| | Ridgeback| 8| | Bloodhound| 12| | Dachshund| 6|

If one puppy is chosen at random, what is the probability it will be either a Ridgeback or a Dachshund?
workedSolution
| | | | ------------: | ---------- | | $P$(R or D) | \= $\dfrac{\text{Number of R and D}}{\text{Total puppies}}$ | | | \= $\dfrac{8 + 6}{32}$ | | | \= {{{correctAnswer}}} |
correctAnswer
$\dfrac{7}{16}$

Answers

Is Correct?Answer
x

37\dfrac{3}{7}

x

916\dfrac{9}{16}

✓

716\dfrac{7}{16}

x

73\dfrac{7}{3}

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