20203

Question

{{name}} is filling a {{number1}}-litre {{container}} with {{content}}.

If {{name}} pours {{number2}} of {{content}} into the {{container}}, what percentage of the {{container}}'s full capacity remains available for more {{content}}?

Worked Solution

Fraction left = number3number1\dfrac{ {{number3}} }{ {{number1}} } = {{frac}}

∴\therefore Percentage remaining
= {{frac}} ×\times 100
= {{{correctAnswer}}}

Variant 0

DifficultyLevel

553

Question

Richard is filling a 1.5-litre jug with cordial.

If Richard pours 1 litre of cordial into the jug, what percentage of the jug's full capacity remains available for more cordial?

Worked Solution

Fraction left = 0.51.5\dfrac{ 0.5 }{ 1.5 } = 13\dfrac{1}{3}

∴\therefore Percentage remaining
= 13\dfrac{1}{3} ×\times 100
= 33.3%

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
name
Richard
number1
1.5
container
jug
content
cordial
number2
1 litre
number3
0.5
frac
$\dfrac{1}{3}$
correctAnswer
33.3%

Answers

Is Correct?Answer
x

15%

x

30%

✓

33.3%

x

50.5%

Variant 1

DifficultyLevel

553

Question

Sally-Anne is filling a 15-litre jerry can with water.

If Sally-Anne pours 6 litres of water into the jerry can, what percentage of the jerry can's full capacity remains available for more water?

Worked Solution

Fraction left = 915\dfrac{ 9 }{ 15 } = 35\dfrac{3}{5}

∴\therefore Percentage remaining
= 35\dfrac{3}{5} ×\times 100
= 60%

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
name
Sally-Anne
number1
15
container
jerry can
content
water
number2
6 litres
number3
9
frac
$\dfrac{3}{5}$
correctAnswer
60%

Answers

Is Correct?Answer
x

40%

x

45%

✓

60%

x

75%

Variant 2

DifficultyLevel

553

Question

Byron is filling a 6-litre petrol can with petrol.

If Byron pours 4 litres of petrol into the petrol can, what percentage of the petrol can's full capacity remains available for more petrol?

Worked Solution

Fraction left = 26\dfrac{ 2 }{ 6 } = 13\dfrac{1}{3}

∴\therefore Percentage remaining
= 13\dfrac{1}{3} ×\times 100
= 33.3%

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
name
Byron
number1
6
container
petrol can
content
petrol
number2
4 litres
number3
2
frac
$\dfrac{1}{3}$
correctAnswer
33.3%

Answers

Is Correct?Answer
x

25%

✓

33.3%

x

44.4%

x

60%

Variant 3

DifficultyLevel

553

Question

Kevin is filling a 12-litre jerry can with water.

If Kevin pours 4 litres of water into the jerry can, what percentage of the jerry can's full capacity remains available for more water?

Worked Solution

Fraction left = 812\dfrac{ 8 }{ 12 } = 23\dfrac{2}{3}

∴\therefore Percentage remaining
= 23\dfrac{2}{3} ×\times 100
= 66.7%

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
name
Kevin
number1
12
container
jerry can
content
water
number2
4 litres
number3
8
frac
$\dfrac{2}{3}$
correctAnswer
66.7%

Answers

Is Correct?Answer
x

30%

x

50.5%

✓

66.7%

x

75%

Variant 4

DifficultyLevel

553

Question

Marty is filling a 15-litre container with liquid chlorine.

If Marty pours 12 litres of liquid chlorine into the container, what percentage of the container's full capacity remains available for more liquid chlorine?

Worked Solution

Fraction left = 315\dfrac{ 3 }{ 15 } = 15\dfrac{1}{5}

∴\therefore Percentage remaining
= 15\dfrac{1}{5} ×\times 100
= 20%

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
name
Marty
number1
15
container
container
content
liquid chlorine
number2
12 litres
number3
3
frac
$\dfrac{1}{5}$
correctAnswer
20%

Answers

Is Correct?Answer
x

5%

✓

20%

x

33.3%

x

66.6%

Tags