Geometry, NAPX9-TLE-39 v3

Question

{{{question}}}

Worked Solution

{{{workedSolution}}}

Variant 0

DifficultyLevel

614

Question

A parallelogram is drawn below.



What is the size of ∠\angleBADBAD?

Worked Solution

Since diagonally opposite angles are equal:
∴\therefore ∠\angleBADBAD = 12(360−(2×130))\dfrac{1}{2} (360 - (2 \times 130))
= 12×100\dfrac{1}{2} \times 100
= 50°\degree

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
A parallelogram is drawn below.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2021/03/NAPX9-TLE-39-2.svg 275 indent2 vpad
What is the size of $\angle$$BAD$?
workedSolution
sm_nogap Since diagonally opposite angles are equal:
||| |-|-| |$\therefore$ $\angle$$BAD$|= $\dfrac{1}{2} (360 - (2 \times 130))$| ||= $\dfrac{1}{2} \times 100$| ||= {{{correctAnswer}}}|
correctAnswer
50$\degree$

Answers

Is Correct?Answer
✓

50°\degree

x

55°\degree

x

60°\degree

x

70°\degree

Variant 1

DifficultyLevel

612

Question

A parallelogram is drawn below.



What is the size of ∠\angleBADBAD?

Worked Solution

Since diagonally opposite angles are equal:
∴\therefore ∠\angleBADBAD = 12(360−(2×50))\dfrac{1}{2} (360 - (2 \times 50))
= 12×260\dfrac{1}{2} \times 260
= 130°\degree

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
A parallelogram is drawn below.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2022/12/Geom_NAPX9-TLE-39-v3_1.svg 275 indent2 vpad
What is the size of $\angle$$BAD$?
workedSolution
sm_nogap Since diagonally opposite angles are equal:
||| |-|-| |$\therefore$ $\angle$$BAD$|= $\dfrac{1}{2} (360 - (2 \times 50))$| ||= $\dfrac{1}{2} \times 260$| ||= {{{correctAnswer}}}|
correctAnswer
130$\degree$

Answers

Is Correct?Answer
x

40°\degree

x

120°\degree

✓

130°\degree

x

140°\degree

Variant 2

DifficultyLevel

610

Question

A parallelogram is drawn below.



What is the size of ∠\angleWXYWXY?

Worked Solution

Since diagonally opposite angles are equal:
∴\therefore ∠\angleWXYWXY = 12(360−(2×120))\dfrac{1}{2} (360 - (2 \times 120))
= 12×120\dfrac{1}{2} \times 120
= 60°\degree

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
A parallelogram is drawn below.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2022/12/Geom_NAPX9-TLE-39-v3_2.svg 275 indent2 vpad
What is the size of $\angle$$WXY$?
workedSolution
sm_nogap Since diagonally opposite angles are equal:
||| |-|-| |$\therefore$ $\angle$$WXY$|= $\dfrac{1}{2} (360 - (2 \times 120))$| ||= $\dfrac{1}{2} \times 120$| ||= {{{correctAnswer}}}|
correctAnswer
60$\degree$

Answers

Is Correct?Answer
x

40°\degree

x

50°\degree

✓

60°\degree

x

70°\degree

Variant 3

DifficultyLevel

608

Question

A parallelogram is drawn below.



What is the size of ∠\angleMPOMPO?

Worked Solution

Since diagonally opposite angles are equal:
∴\therefore ∠\angleMPOMPO = 12(360−(2×40))\dfrac{1}{2} (360 - (2 \times 40))
= 12×280\dfrac{1}{2} \times 280
= 140°\degree

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
A parallelogram is drawn below.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2022/12/Geom_NAPX9-TLE-39-v3_3.svg 355 indent2 vpad
What is the size of $\angle$$MPO$?
workedSolution
sm_nogap Since diagonally opposite angles are equal:
||| |-|-| |$\therefore$ $\angle$$MPO$|= $\dfrac{1}{2} (360 - (2 \times 40))$| ||= $\dfrac{1}{2} \times 280$| ||= {{{correctAnswer}}}|
correctAnswer
140$\degree$

Answers

Is Correct?Answer
x

50°\degree

x

80°\degree

x

100°\degree

✓

140°\degree

Variant 4

DifficultyLevel

606

Question

A parallelogram is drawn below.



What is the size of ∠\angleQRSQRS?

Worked Solution

Since diagonally opposite angles are equal:
∴\therefore ∠\angleQRSQRS = 12(360−(2×105))\dfrac{1}{2} (360 - (2 \times 105))
= 12×150\dfrac{1}{2} \times 150
= 75°\degree

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
A parallelogram is drawn below.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2022/12/Geom_NAPX9-TLE-39-v3_4.svg 175 indent2 vpad
What is the size of $\angle$$QRS$?
workedSolution
sm_nogap Since diagonally opposite angles are equal:
||| |-|-| |$\therefore$ $\angle$$QRS$|= $\dfrac{1}{2} (360 - (2 \times 105))$| ||= $\dfrac{1}{2} \times 150$| ||= {{{correctAnswer}}}|
correctAnswer
75$\degree$

Answers

Is Correct?Answer
✓

75°\degree

x

80°\degree

x

85°\degree

x

210°\degree

Variant 5

DifficultyLevel

607

Question

A parallelogram is drawn below.



What is the size of ∠\anglePQRPQR?

Worked Solution

Since diagonally opposite angles are equal:
∴\therefore ∠\anglePQRPQR = 12(360−(2×77))\dfrac{1}{2} (360 - (2 \times 77))
= 12×206\dfrac{1}{2} \times 206
= 103°\degree

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
A parallelogram is drawn below.
sm_img https://teacher.smartermaths.com.au/wp-content/uploads/2022/12/Geom_NAPX9-TLE-39-v3_5.svg 175 indent2 vpad
What is the size of $\angle$$PQR$?
workedSolution
sm_nogap Since diagonally opposite angles are equal:
||| |-|-| |$\therefore$ $\angle$$PQR$|= $\dfrac{1}{2} (360 - (2 \times 77))$| ||= $\dfrac{1}{2} \times 206$| ||= {{{correctAnswer}}}|
correctAnswer
103$\degree$

Answers

Is Correct?Answer
x

13°\degree

✓

103°\degree

x

154°\degree

x

206°\degree

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