Number, NAPX-p107114v02 SA

Question

{{{question}}}

Worked Solution

{{{workedSolution}}}

Variant 0

DifficultyLevel

651

Question

A charity calculates its total donations every month.

Over a six month period, the amounts they calculate are as follows:

$1520, $1270, $1600, $1310, $1430, $1288


What is the mean monthly donation the charity received over this 6 month period?

Worked Solution
Mean = 1520+1270+1600+1310+1430+12886\dfrac{1520+1270+1600+1310+1430+1288}{6}
= 84186\dfrac{8418}{6}
= $1403

Question Type

Answer Box

Variables

Variable nameVariable value
question
A charity calculates its total donations every month. Over a six month period, the amounts they calculate are as follows: > > $1520, $1270, $1600, $1310, $1430, $1288
What is the mean monthly donation the charity received over this 6 month period?
workedSolution
| | | | ------------: | ---------- | | Mean | \= $\dfrac{1520+1270+1600+1310+1430+1288}{6}$ | | | \= $\dfrac{8418}{6}$| | | \= {{{prefix0}}}{{{correctAnswer0}}} |
correctAnswer0
1403
prefix0
$
suffix0

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer01403

$

Variant 1

DifficultyLevel

653

Question

A carwash calculates its total receipts every month.

Over a six month period, the amounts they calculate are as follows:

$31 450, $29 465, $24 385, $25 460, $28 700, $26 344


What is the mean monthly amount the carwash received over this 6 month period?

Worked Solution
Mean = 31 450+29 464+24 385+25 460+28 700+26 3446\dfrac{31\ 450+29\ 464+24\ 385+25\ 460+28\ 700+26\ 344}{6}
= 165 8046\dfrac{165\ 804}{6}
= $27 634

Question Type

Answer Box

Variables

Variable nameVariable value
question
A carwash calculates its total receipts every month. Over a six month period, the amounts they calculate are as follows: > > $31 450, $29 465, $24 385, $25 460, $28 700, $26 344
What is the mean monthly amount the carwash received over this 6 month period?
workedSolution
| | | | ------------: | ---------- | | Mean | \= $\dfrac{31\ 450+29\ 464+24\ 385+25\ 460+28\ 700+26\ 344}{6}$ | | | \= $\dfrac{165\ 804}{6}$| | | \= $27 634 |
correctAnswer0
27634
prefix0
$
suffix0

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer027634

$

Variant 2

DifficultyLevel

654

Question

Gerwyn is recycling bottles and cans and calculates the amount he receives at the recycling depot.

Over a six week period, the amounts he calculates are as follows:

$16.70, $12.70, $21.40, $14.10, $18.30, $12.80


What is the mean weekly recycling amount Gerwyn received over this 6 week period?

Worked Solution
Mean = 16.70+12.70+21.40+14.10+18.30+12.806\dfrac{16.70+12.70+21.40+14.10+18.30+12.80}{6}
= 966\dfrac{96}{6}
= $16

Question Type

Answer Box

Variables

Variable nameVariable value
question
Gerwyn is recycling bottles and cans and calculates the amount he receives at the recycling depot. Over a six week period, the amounts he calculates are as follows: > > $16.70, $12.70, $21.40, $14.10, $18.30, $12.80
What is the mean weekly recycling amount Gerwyn received over this 6 week period?
workedSolution
| | | | ------------: | ---------- | | Mean | \= $\dfrac{16.70+12.70+21.40+14.10+18.30+12.80}{6}$ | | | \= $\dfrac{96}{6}$| | | \= {{{prefix0}}}{{{correctAnswer0}}} |
correctAnswer0
16
prefix0
$
suffix0

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer016

$

Variant 3

DifficultyLevel

656

Question

Bexley owns a delivery truck and calculates his delivery charges every month.

Over a six month period, the amounts he calculated are as follows:

$2452, $3400, $4510, $3567, $1243, $890


What is the mean monthly amount Bexley received over this 6 month period?

Worked Solution
Mean = 2452+3400+4510+3567+1243+8906\dfrac{2452+3400+4510+3567+1243+890}{6}
= 16 0626\dfrac{16\ 062}{6}
= $2677

Question Type

Answer Box

Variables

Variable nameVariable value
question
Bexley owns a delivery truck and calculates his delivery charges every month. Over a six month period, the amounts he calculated are as follows: > > $2452, $3400, $4510, $3567, $1243, $890
What is the mean monthly amount Bexley received over this 6 month period?
workedSolution
| | | | ------------: | ---------- | | Mean | \= $\dfrac{2452+3400+4510+3567+1243+890}{6}$ | | | \= $\dfrac{16\ 062}{6}$| | | \= {{{prefix0}}}{{{correctAnswer0}}} |
correctAnswer0
2677
prefix0
$
suffix0

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer02677

$

Variant 4

DifficultyLevel

658

Question

A parking station records the total number of cars parking there every day.

Over a seven day period, the numbers of cars parking are recorded as follows:

846, 465, 786, 345, 682, 987, 782


What is the mean number of cars parking over this 7 day period?

Worked Solution
Mean = 846+465+786+345+682+987+7827\dfrac{846+465+786+345+682+987+782}{7}
= 48937\dfrac{4893}{7}
= 699 cars

Question Type

Answer Box

Variables

Variable nameVariable value
question
A parking station records the total number of cars parking there every day. Over a seven day period, the numbers of cars parking are recorded as follows: > > 846, 465, 786, 345, 682, 987, 782
What is the mean number of cars parking over this 7 day period?
workedSolution
| | | | ------------: | ---------- | | Mean | \= $\dfrac{846+465+786+345+682+987+782}{7}$ | | | \= $\dfrac{4893}{7}$| | | \= {{{correctAnswer0}}} {{{suffix0}}} |
correctAnswer0
699
prefix0
suffix0
cars

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer0699

cars

Variant 5

DifficultyLevel

660

Question

A landscaping company calculates the total number of kilograms of topsoil it sells every day.

Over a seven day period, the amount of topsoil sold is calculated as follows:

345, 476, 256, 360, 481, 950, 240,


What is the mean amount of topsoil sold over this 7 day period?

Worked Solution
Mean = 345+476+256+360+481+950+2407\dfrac{345+476+256+360+481+950+240}{7}
= 31087\dfrac{3108}{7}
= 444 kilograms

Question Type

Answer Box

Variables

Variable nameVariable value
question
A landscaping company calculates the total number of kilograms of topsoil it sells every day. Over a seven day period, the amount of topsoil sold is calculated as follows: > > 345, 476, 256, 360, 481, 950, 240,
What is the mean amount of topsoil sold over this 7 day period?
workedSolution
| | | | ------------: | ---------- | | Mean | \= $\dfrac{345+476+256+360+481+950+240}{7}$ | | | \= $\dfrac{3108}{7}$| | | \= {{{correctAnswer0}}} {{{suffix0}}} |
correctAnswer0
444
prefix0
suffix0
kilograms

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer0444

kilograms

Tags

  • ms_ca