Algebra, NAP_22045

Question

{{{question}}}

Worked Solution

{{{workedSolution}}}

Variant 0

DifficultyLevel

646

Question

Vlad uses the formula below to estimate the population of wombats in Kosciuszko National Park over a three year period.

Year 1 = 900


Year 2 = Year 1 + Year 130\dfrac{ \text{Year 1}}{30}


Year 3 = Year 2 + Year 230\dfrac{ \text{Year 2}}{30}


Estimate the population of wombats in Kosciuszko National Park in Year 3?

Worked Solution

Year 1 = 900

Year 2 = 900 + 90030\dfrac{900}{30} = 930

Year 3 = 930 + 93030\dfrac{930}{30} = 961

Question Type

Answer Box

Variables

Variable nameVariable value
question
Vlad uses the formula below to estimate the population of wombats in Kosciuszko National Park over a three year period. >Year 1 = 900
>Year 2 = Year 1 + $\dfrac{ \text{Year 1}}{30}$
>Year 3 = Year 2 + $\dfrac{ \text{Year 2}}{30}$
Estimate the population of wombats in Kosciuszko National Park in Year 3?
workedSolution
Year 1 = 900 Year 2 = 900 + $\dfrac{900}{30}$ = 930 Year 3 = 930 + $\dfrac{930}{30}$ = {{{correctAnswer0}}}
correctAnswer0
961
prefix0
suffix0
wombats

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer0961

wombats

Variant 1

DifficultyLevel

648

Question

Morgan uses the formula below to estimate the population of Tasmanian devils in a breeding program over a three year period.

Year 1 = 300


Year 2 = Year 1 + Year 110\dfrac{ \text{Year 1}}{10}


Year 3 = Year 2 + Year 210\dfrac{ \text{Year 2}}{10}


Estimate the population of Tasmanian devils in Year 3?

Worked Solution

Year 1 = 300

Year 2 = 300 + 30010\dfrac{300}{10} = 330

Year 3 = 330 + 33010\dfrac{330}{10} = 363

Question Type

Answer Box

Variables

Variable nameVariable value
question
Morgan uses the formula below to estimate the population of Tasmanian devils in a breeding program over a three year period. >Year 1 = 300
>Year 2 = Year 1 + $\dfrac{ \text{Year 1}}{10}$
>Year 3 = Year 2 + $\dfrac{ \text{Year 2}}{10}$
Estimate the population of Tasmanian devils in Year 3?
workedSolution
Year 1 = 300 Year 2 = 300 + $\dfrac{300}{10}$ = 330 Year 3 = 330 + $\dfrac{330}{10}$ = {{{correctAnswer0}}}
correctAnswer0
363
prefix0
suffix0
Tasmanian devils

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer0363

Tasmanian devils

Variant 2

DifficultyLevel

650

Question

Kurt uses the formula below to estimate the population of humpback whales in the Eastern migration over a three year period.

Year 1 = 40 000


Year 2 = Year 1 + Year 140\dfrac{ \text{Year 1}}{40}


Year 3 = Year 2 + Year 240\dfrac{ \text{Year 2}}{40}


Estimate the population of humpback whales in Year 3?

Worked Solution

Year 1 = 40000

Year 2 = 40000 + 4000040\dfrac{40000}{40} = 41000

Year 3 = 41000 + 4100040\dfrac{41000}{40} = 42025

Question Type

Answer Box

Variables

Variable nameVariable value
question
Kurt uses the formula below to estimate the population of humpback whales in the Eastern migration over a three year period. >Year 1 = 40 000
>Year 2 = Year 1 + $\dfrac{ \text{Year 1}}{40}$
>Year 3 = Year 2 + $\dfrac{ \text{Year 2}}{40}$
Estimate the population of humpback whales in Year 3?
workedSolution
Year 1 = 40000 Year 2 = 40000 + $\dfrac{40000}{40}$ = 41000 Year 3 = 41000 + $\dfrac{41000}{40}$ = {{{correctAnswer0}}}
correctAnswer0
42025
prefix0
suffix0
humpback whales

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer042025

humpback whales

Variant 3

DifficultyLevel

652

Question

Bianca uses the formula below to estimate the population of female sea turtles on the Caribbean coast over a three year period.

Year 1 = 30000


Year 2 = Year 1 + Year 130\dfrac{ \text{Year 1}}{30}


Year 3 = Year 2 + Year 230\dfrac{ \text{Year 2}}{30}


Estimate the population of female sea turtles in Year 3?

Worked Solution

Year 1 = 30000

Year 2 = 30000 + 3000020\dfrac{30000}{20} = 31500

Year 3 = 31500 + 3150020\dfrac{31500}{20} = 33075

Question Type

Answer Box

Variables

Variable nameVariable value
question
Bianca uses the formula below to estimate the population of female sea turtles on the Caribbean coast over a three year period. >Year 1 = 30000
>Year 2 = Year 1 + $\dfrac{ \text{Year 1}}{30}$
>Year 3 = Year 2 + $\dfrac{ \text{Year 2}}{30}$
Estimate the population of female sea turtles in Year 3?
workedSolution
Year 1 = 30000 Year 2 = 30000 + $\dfrac{30000}{20}$ = 31500 Year 3 = 31500 + $\dfrac{31500}{20}$ = {{{correctAnswer0}}}
correctAnswer0
33075
prefix0
suffix0
sea turtles

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer033075

sea turtles

Variant 4

DifficultyLevel

654

Question

Gina uses the formula below to estimate the population of fairy penguins on Phillip Island over a three year period.

Year 1 = 32000


Year 2 = Year 1 + Year 116\dfrac{ \text{Year 1}}{16}


Year 3 = Year 2 + Year 216\dfrac{ \text{Year 2}}{16}


Estimate the population of fairy penguins in Year 3?

Worked Solution

Year 1 = 32000

Year 2 = 32000 + 3200016\dfrac{32000}{16} = 34000

Year 3 = 34000 + 3400016\dfrac{34000}{16} = 36125

Question Type

Answer Box

Variables

Variable nameVariable value
question
Gina uses the formula below to estimate the population of fairy penguins on Phillip Island over a three year period. >Year 1 = 32000
>Year 2 = Year 1 + $\dfrac{ \text{Year 1}}{16}$
>Year 3 = Year 2 + $\dfrac{ \text{Year 2}}{16}$
Estimate the population of fairy penguins in Year 3?
workedSolution
Year 1 = 32000 Year 2 = 32000 + $\dfrac{32000}{16}$ = 34000 Year 3 = 34000 + $\dfrac{34000}{16}$ = {{{correctAnswer0}}}
correctAnswer0
36125
prefix0
suffix0
fairy penguins

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer036125

fairy penguins

Variant 5

DifficultyLevel

656

Question

Skippy uses the formula below to estimate the population of kangaroos in New South Wales over a three year period.

Year 1 = 11.8 million


Year 2 = Year 1 + Year 110\dfrac{ \text{Year 1}}{10}


Year 3 = Year 2 + Year 210\dfrac{ \text{Year 2}}{10}


Estimate the population of kangaroos in New South Wales in Year 3?

Worked Solution

Year 1 = 11 800 000

Year 2 = 11 800 000 + 1180000010\dfrac{11 800 000}{10} = 12980000

Year 3 = 12 980 000 + 1298000010\dfrac{12 980 000}{10} = 14278000

Question Type

Answer Box

Variables

Variable nameVariable value
question
Skippy uses the formula below to estimate the population of kangaroos in New South Wales over a three year period. >Year 1 = 11.8 million
>Year 2 = Year 1 + $\dfrac{ \text{Year 1}}{10}$
>Year 3 = Year 2 + $\dfrac{ \text{Year 2}}{10}$
Estimate the population of kangaroos in New South Wales in Year 3?
workedSolution
Year 1 = 11 800 000 Year 2 = 11 800 000 + $\dfrac{11 800 000}{10}$ = 12980000 Year 3 = 12 980 000 + $\dfrac{12 980 000}{10}$ = {{{correctAnswer0}}}
correctAnswer0
14278000
prefix0
suffix0
kangaroos

Answers

Specify one or more 'ANSWER' block(s) as exampled below.
Note: correctAnswer is required, the rest are optional. ("correctAnswer" is what the student would need to type in to the box to get the answer correct.)

For example:
correctAnswer: 123.40

And optionally, specify the following, but only if you need something different to the defaults: 'width' defaults to 5 if not present, and valid values are 3 to 10; 'prefix' and 'suffix' default to nothing if not present.
prefix: $
suffix: mm$^2$
width: 5

correctAnswerNcorrectAnswerValueAnswer
correctAnswer014278000

kangaroos

Tags

  • staging_suejones