RAPH14 Q91-93

Question

{{{question}}}

Worked Solution

{{{workedSolution}}}

Variant 0

DifficultyLevel

517

Question

Matt, Trish, and Kent went to a pizza restaurant.

Matt and Trish each ate 18\dfrac{1}{8} of the pizza served.

What fraction of the pizza was left for Kent?

Worked Solution
Pizza left = 1 – ( 18\dfrac{1}{8} + 18\dfrac{1}{8} )
= 1 – 14\dfrac{1}{4}
= 44\dfrac{4}{4} – 14\dfrac{1}{4}
= 34\dfrac{3}{4}

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
Matt, Trish, and Kent went to a pizza restaurant. Matt and Trish each ate $\dfrac{1}{8}$ of the pizza served. What fraction of the pizza was left for Kent?
workedSolution
| | | | ------------- | ---------- | | Pizza left | \= 1 – ( $\dfrac{1}{8}$ + $\dfrac{1}{8}$ ) | | | \= 1 – $\dfrac{1}{4}$ | | | \= $\dfrac{4}{4}$ – $\dfrac{1}{4}$ | | | \= {{{correctAnswer}}} |
correctAnswer
$\dfrac{3}{4}$

Answers

Is Correct?Answer
✓

34\dfrac{3}{4}

x

14\dfrac{1}{4}

x

58\dfrac{5}{8}

x

78\dfrac{7}{8}

Variant 1

DifficultyLevel

519

Question

Ruth, April, and Yoni shared a box of chocolates.

Ruth and April each ate 16\dfrac{1}{6} of the chocolates in the box.

What fraction of the chocolates were left for Yoni?

Worked Solution
Chocolates left = 1 – ( 16\dfrac{1}{6} + 16\dfrac{1}{6} )
= 1 – 26\dfrac{2}{6}
= 66\dfrac{6}{6} – 26\dfrac{2}{6}
= 46\dfrac{4}{6}

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
Ruth, April, and Yoni shared a box of chocolates. Ruth and April each ate $\dfrac{1}{6}$ of the chocolates in the box. What fraction of the chocolates were left for Yoni?
workedSolution
| | | | ------------- | ---------- | | Chocolates left | \= 1 – ( $\dfrac{1}{6}$ + $\dfrac{1}{6}$ ) | | | \= 1 – $\dfrac{2}{6}$ | | | \= $\dfrac{6}{6}$ – $\dfrac{2}{6}$ | | | \= {{{correctAnswer}}} |
correctAnswer
$\dfrac{4}{6}$

Answers

Is Correct?Answer
x

26\dfrac{2}{6}

x

36\dfrac{3}{6}

✓

46\dfrac{4}{6}

x

16\dfrac{1}{6}

Variant 2

DifficultyLevel

521

Question

Manuel, Jericho, and Tom shared a bucket of fried chicken.

Manuel and Jericho each ate 37\dfrac{3}{7} of the fried chicken.

What fraction of the fried chicken was left for Tom?

Worked Solution
Fried chicken left = 1 – ( 37\dfrac{3}{7} + 37\dfrac{3}{7} )
= 1 – 67\dfrac{6}{7}
= 77\dfrac{7}{7} – 67\dfrac{6}{7}
= 17\dfrac{1}{7}

Question Type

Multiple Choice (One Answer)

Variables

Variable nameVariable value
question
Manuel, Jericho, and Tom shared a bucket of fried chicken. Manuel and Jericho each ate $\dfrac{3}{7}$ of the fried chicken. What fraction of the fried chicken was left for Tom?
workedSolution
| | | | ------------- | ---------- | | Fried chicken left | \= 1 – ( $\dfrac{3}{7}$ + $\dfrac{3}{7}$ ) | | | \= 1 – $\dfrac{6}{7}$ | | | \= $\dfrac{7}{7}$ – $\dfrac{6}{7}$ | | | \= {{{correctAnswer}}} |
correctAnswer
$\dfrac{1}{7}$

Answers

Is Correct?Answer
✓

17\dfrac{1}{7}

x

47\dfrac{4}{7}

x

67\dfrac{6}{7}

x

37\dfrac{3}{7}

Tags